4+5/x^2=6/x

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Solution for 4+5/x^2=6/x equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

5/(x^2)+4 = 6/x // - 6/x

5/(x^2)-(6/x)+4 = 0

5/(x^2)-6*x^-1+4 = 0

5*x^-2-6*x^-1+4 = 0

t_1 = x^-1

5*t_1^2-6*t_1^1+4 = 0

5*t_1^2-6*t_1+4 = 0

DELTA = (-6)^2-(4*4*5)

DELTA = -44

DELTA < 0

x belongs to the empty set

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